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Steamulator Solved Examples
Compressed Water |
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Properties of Compressed Water
The following properties of
compressed water can be found using Steamulator:
T, P, V, U, H, S
if any one pair of the following properties is given:
(T, P), (T, V), (T, U), (T, H), (T, S), (P, V), (P, U), (P, H), (P,
S)
Examples |
Given "T, P"
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Find H,
S, V & U in the "US" unit system for a compressed water with
temperature of 675゜F and pressure of 5000 Psia.
Sub Region: Compressed Water
Units: US
Given: T = 675゜F & P = 5000 Psia
Find: H
Answer: H = 707.8762 Btu/lbm
Find: S
Answer: S = 0.8820 Btu/lbm/R
Find: V
Answer: V = 0.025082 ft3/lbm
Find: U
Answer: U = 684.6690 Btu/lbm
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Given
"T, V"
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Find P,
H & S in the "US" unit system for a compressed water with
temperature of 500゜F and a specific volume of 0.02 ft3/lbm.
Sub Region: Compressed Water
Units: US
Given: T = 500゜F & V = 0.02 ft3/lbm
Find: P
Answer: P = 2731.4560 Psia
Find: H
Answer: H = 487.5038 Btu/lbm
Find: S
Answer: S = 0.6806 Btu/lbm/R
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Given
"T, U"
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Find P,
H & S in the "US" unit system for a compressed water with
temperature of 600゜F and a specific internal energy of 584 Btu/lbm.
Sub Region: Compressed Water
Units: US
Given: T = 600゜F & U = 584 Btu/lbm
Find: P
Answer: P = 5059.4457 Psia
Find: H
Answer: H = 604.5193 Btu/lbm
Find: S
Answer: S = 0.7876 Btu/lbm/R
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Given
"T, H"
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Find P &
S in the "US" unit system for a compressed water with temperature of
200゜F and a specific enthalpy of 170 Btu/lbm.
Sub Region: Compressed Water
Units: US
Given: T = 200゜F & H = 170 Btu/lbm
Find: P
Answer: P = 854.8710 Psia
Find: S
Answer: S = 0.2930 Btu/lbm/R
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Given
"T, S" |
Find P &
H in the "US" unit system for a compressed water with temperature of
400゜F and a specific entropy of 0.566 Btu/lbm/R.
Sub Region: Compressed Water
Units: US
Given: T = 400゜F & S = 0.566 Btu/lbm/R
Find: P
Answer: P = 499.3813 Psia
Find: H
Answer: H = 375.3790 Btu/lbm
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Given
"P, V" |
Find T,
H & S in the "US" unit system for a compressed water with pressure
of 10000 Psia and a specific volume of 0.016 ft3/lbm.
Sub Region: Compressed Water
Units: US
Given: P = 10000 Psia & V = 0.016 ft3/lbm
Find: T
Answer: T = 173.5996゜F
Find: H
Answer: H = 165.2224 Btu/lbm
Find: S
Answer: S = 0.2430 Btu/lbm/R
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Given
"P, U" |
Find T,
H, S & V in the "US" unit system for a compressed water with
pressure of 7500 Psia and a specific internal energy of 300 Btu/lbm.
Sub Region: Compressed Water
Units: US
Given: P = 7500 Psia & U = 300 Btu/lbm
Find: T
Answer: T = 339.9805゜F
Find: H
Answer: H = 324.0187 Btu/lbm
Find: S
Answer: S = 0.4762 Btu/lbm/R
Find: V
Answer: V = 0.017306 ft3/lbm
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Given
"P, H" |
Find T,
V & S in the "US" unit system for a compressed water with pressure
of 5000 Psia and a specific enthalpy of 250 Btu/lbm.
Sub Region: Compressed Water
Units: US
Given: P = 5000 Psia & H = 250 Btu/lbm
Find: T
Answer: T = 271.0038゜F
Find: V
Answer: V = 0.016869 ft3/lbm
Find: S
Answer: S = 0.3897 Btu/lbm/R
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Given
"P, S" |
Find T,
V & H in the "US" unit system for a compressed water with pressure
of 2000 Psia and a specific entropy of 0.7 Btu/lbm/R.
Sub Region: Compressed Water
Units: US
Given: P = 2000 Psia & S = 0.7 Btu/lbm/R
Find: T
Answer: T = 513.7018゜F
Find: V
Answer: V = 0.020453 ft3/lbm
Find: H
Answer: H = 503.5265 Btu/lbm |
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