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Steamulator Solved Examples
Saturated Water |
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Properties of Saturated Water
The following properties of saturated
water can be found using Steamulator:
T, P, Vf, Vfg, Vg, Uf, Ufg,
Ug, Hf, Hfg, Hg, Sf,
Sfg, Sg
if one of the following properties is given:
T, P, Vf, Uf, Hf, Sf
Examples |
Given "T"
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Find
pressure in "Psia" for a saturated water with a saturated
temperature of 185゜F.
Sub Region: Saturated Water
Units: US
Given: T=185゜F
Find: P
Answer: P = 8.3837 Psia
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Given
"P"
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Find
temperature in "C" for a saturated water with a saturated pressure
of 0.1 MPa.
Sub Region: Saturated Water
Units: SI
Given: P=0.1 MPa
Find: T
Answer: T = 99.6316゜C
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Given "Vf"
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Find
specific entropy in the "US" unit system for a saturated water with
a specific volume of 0.025 ft3/lbm.
Sub Region: Saturated Water
Units: US
Given: Vf=0.025 ft3/lbm
Find: Sf
Answer: Sf = 0.8483
Btu/lbm/R
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Given "Uf"
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Find
temperature in "C" and pressure in "in Hg" for a saturated water
with a specific internal energy of 500 Btu/lbm.
Sub Region: Saturated Water
Units: Custom, T: C; P: in Hg; U: Btu/lbm
Given: Uf=500
Btu/lbm
Find: T
Answer: T = 266.9557゜C
Find: P
Answer: P = 1549.8119 in Hg
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Given "Hf" |
Find
temperature in "F" for a saturated water with a specific enthalpy of
0.1 kW-hr/lbm.
Sub Region: Saturated Water
Units: Custom, T: F; H: kW-hr/lbm
Given: Hf=0.1 kW-hr/lbm
Find: T
Answer: T = 368.4026゜F
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Given "Sf" |
Find
temperature in "C" and specific volume in "cm3/g" for a
saturated water with a specific entropy of 1.3 J/g/K.
Sub Region: Saturated Water
Units: Metric
Given: Sf=1.3 J/g/K
Find: T
Answer: T = 99.3921゜C
Find: Vf
Answer: Vf =
1.043232 cm3/g
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